1000=-0.03x^2+x

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Solution for 1000=-0.03x^2+x equation: 



1000=-0.03x^2+x

We move all terms to the left:

1000-(-0.03x^2+x)=0

We get rid of parentheses

0.03x^2-x+1000=0

We add all the numbers together, and all the variables

0.03x^2-1x+1000=0

a = 0.03; b = -1; c = +1000;
Δ = b2-4ac
Δ = -12-4·0.03·1000
Δ = -119
Delta is less than zero, so there is no solution for the equation

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